Trigonometric Identities Proof

AI Thread Summary
The discussion focuses on deriving trigonometric identities using fundamental equalities. Key identities include sin(-x) = -sin x and cos(-x) = cos x, which are essential for proving other equations. Participants express difficulty in deriving the absolute values of cos x/2 and sin x/2, seeking clarification on the process. Suggestions include setting A equal to B in the cosine addition formula and adjusting variables accordingly. The conversation emphasizes the importance of correctly applying trigonometric properties to achieve the desired results.
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1. (A) sin(-x) = - sin x (C) cos(x+y) = cosxcosy - sinxsiny
(B) cos(-x) = - cos x (D) sin(x+y) = sinxcosy + cosxsiny
Use these equalities to derive the following trigonometric identities.
a. absolute value of cos x/2 = \sqrt{}1 + cosx/2
b. absolute value of sin x/2 = \sqrt{}1 - cosx/2



2.above



3. I'm stuck on these two and tried to think of different ways to solve it but I can't seem to get find a solution to it. Can you please explain how to derive those two equations? Thank You!
 
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cos(A+B) = cosAcosB - sinAsinB, try setting A=B and then see what happens. Since there is an x/2, maybe you should replace A with that.
 
(B) cos(-x) = - cos x
needs to be cos(-x) = cos x without the minus in front on the right side.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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