How do i find the mass of a mysteryious object?

  • Thread starter Thread starter elpermic
  • Start date Start date
  • Tags Tags
    Mass
AI Thread Summary
To find the mass of a mysterious object when only the area is known, the mass per unit area must also be determined. In this case, the average mass per unit area from a previous lab is 0.285824 g/cm². By multiplying this average by the object's area in cm², the total mass can be calculated. This method confirms that knowing both area and mass per unit area is essential for calculating mass. Therefore, the approach of multiplying the average mass per unit area by the area is correct.
elpermic
Messages
29
Reaction score
0

Homework Statement


i'm suppose to find the mass of a mysterious object(a tile)i i know the area, which is centimeters squared, and asked to find the mass. would i just multiple g/cm^2 and my area together to get the mass?


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Unless you know the mass per unit area you can't get the mass from the area alone.
 
well the average mass per unit area we had from this lab was 0.285824 g/cm^2. so if i multiplied the average x area i would get the mass?
 
elpermic said:
well the average mass per unit area we had from this lab was 0.285824 g/cm^2. so if i multiplied the average x area i would get the mass?

then yes.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top