Calculating Gauge Pressure in a Closed Tube

AI Thread Summary
To calculate the gauge pressure at point A in the closed tube filled with oil, the relevant formula is gauge pressure = (density)gh. The density of the oil is specified as 900 kg/m³, and the height (h) is 0.5 m. One participant calculated the gauge pressure to be 4,400 Pa by first determining total pressure and then subtracting atmospheric pressure, while another clarified that it is unnecessary to calculate total pressure. The discussion emphasizes the importance of using the correct approach to find gauge pressure directly. The correct gauge pressure calculation method is highlighted for clarity.
Beastegargoyl
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Homework Statement


The container shown in the figure is filled with oil. It is open to the atmosphere on the left.
What is the gauge pressure at point A? Point A is 50cm high from the ground and 50 cm from the top.

Homework Equations


po+(density)gd



The Attempt at a Solution


I took 1 atompshere in Pa of 1.013*105+900*G which is 9.8*.5m and I came up with an answer of 1.057 then I subtracted the gauge pressure of 101.3 kPa and solved for the final answer to be 4,400Pa.

Does anyone come up with the same answer?
 
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What's the density of the oil? Gauge pressure is just (density)gh, so you don't have to calculate total pressure and then subtract atmospheric pressure.
 
The denisty of oil is 900kg/m3
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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