Circuit Problem: Finding the Correct Solution for a Voltage Calculation

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The discussion revolves around a circuit problem involving voltage calculations, where the user presents two solutions but is unsure of their correctness. In the first solution, the user calculates Ix as 2.86 mA and Vo as 11.4 V, while the second solution yields Ix as approximately 0.00998 mA and Vo as 39.9 V. The user seeks clarification on which solution is accurate and where any mistakes may lie. Other participants are encouraged to share their attempts at solving the problem. The thread has been moved to the homework help section for better assistance.
ninaricci
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circuit problem, please need help??

Hi,
I am going to be so pleased if somebody helped me with the problem in the attached file
best wishes :confused: :confused:
here is my solution but i do not know where the mistake is
solution number 1

4-ix-vo/10=0
V of 20k = vo of 10 = 4Ix
Using eq 1…..4-ix-4Ix/10=0
4-1.4Ix=0
4=1.4Ix
4/1.4=Ix
= 2.86ma
Vo=4*2.86 = 11.4v


Solution number 2

Combing 10 kohm and 10 kohm = 20 since they are in series
Voltage of 20 kohm the resultant is = 4000Ix
4000Ix/20 = I of 20 kohm……200Ix = I of 20 kohm
Kcl
4mA-Ix –Iof vo = 0
4ma-Ix – 4000Ix/10
4ma-Ix – 400Ix = 0
4ma -401Ix =0
4ma = 401 Ix
4ma/401 = Ix
Ix= 0.00998mA
Vo = Io of vo * 10 kohm
4mA-0.00998-Io of vo = 0
Io of vo = 3. 99 ma
Vo = 3.99* 10 = 39 .9V
which solution is correct and if thre is amistake where is it
 

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ninaricci,

please post what you've tried for this problem.

I'm moving the thread to homework help.
 
Too late, I gave her an answer in the General Physics forum. She posted it there too.
 

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