How Accurate is My Solution for IC and VCE in a Silicon Transistor Circuit?

  • Thread starter Thread starter martyg314
  • Start date Start date
  • Tags Tags
    Circuit Transistor
martyg314
Messages
5
Reaction score
0
This is for a 300 level electronics lab class and I'm wondering if I'm close:

Homework Statement



If the following silicon transistor (VBE = 0.6 V) has a B value of 100, determine IC and VCE.

Homework Equations



http://img862.imageshack.us/img862/80/circuit1.th.jpg

Uploaded with ImageShack.us

The Attempt at a Solution



First I found an expression for \alpha (0.99) and noted that
VBC=VCE-0.6

Then I used Kirchoff's laws for the BE loop and the "loop" from the -15 V down to ground:

BE Loop:
-15 + 2000IC + VCE + 1000IE = 0
-15 + 2990IC + VCE = 0

15 V to Ground:
-15 + 40000IB +VBC + 2000IC = 0
-15.6 + 2400IC + VCE =0

I then solved these equations to get:
IC = 1 mA
VCE = 18.04 V

Any tips would be greatly appreciated.

Also, if anyone can recommend a good electronics text. Mine (Principles of Electronic Instrumentation by Diefenderfer) is filled with errors and is short on example problems.

Thanks,

MG

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited by a moderator:
Physics news on Phys.org
It might be profitable to replace the base bias network with a Thevenin equivalent. Then the only loop you need to concentrate on will be the one containing the base-emitter.

Emitter current should be IE = IB(β + 1). Then, knowing VBE = -0.6V, you should have everything required to solve for IB, thence IC.
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...

Similar threads

Replies
3
Views
2K
Replies
4
Views
1K
Replies
13
Views
2K
Replies
4
Views
3K
Replies
2
Views
4K
Replies
4
Views
3K
Replies
1
Views
2K
Replies
3
Views
2K
Back
Top