Calculating the Rate of Nuclear Fission with 1000 kW Power and 200 MeV Energy

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To calculate the rate of nuclear fission, the energy produced per fission of U-235 is 200 MeV, which converts to approximately 3.2 x 10^-11 joules. Given a reactor power output of 1000 kW, or 1,000,000 joules per second, the total energy per second can be expressed as dE/dt. The relationship between energy per fission (dE/dN) and power (dE/dt) allows for the calculation of fission reactions per second (dN/dt). By dividing the total power output by the energy produced per fission, the rate of nuclear fission can be determined.
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200 MeV of energy may be obtained per fission of U 235. A reactor is generating 1000 Kw of power. Find the rate of nuclear fission ?
Please help...
 
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You know the power, and you now the energy per fission. What are their definitions? How do you use them to get fission per second?
 
Last edited:
P = dW/dt = 1000000J/s

1 fission = 200 MeV = . . .
 
You know that one fission gives 200 MeV energy. So the amount of energy per fission reaction is 200 MeV per fission reaction. If N is the number of fission reactions, this can be expressed as dE/dN. Now you want to find fission reaction per second, dN/dt.

How do you get dN/dt with dE/dN and dE/dt (power)?
 

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