Electric field due to point charge

AI Thread Summary
The discussion centers on calculating the magnitude of a point charge that produces an electric field of 2 nC at a distance of 50 cm. The correct formula for the electric field due to a point charge is E = (1/4πε₀) * (q/r²), where ε₀ is the permittivity of free space. A participant initially calculated the charge to be 71.92 pC, but it was pointed out that the correct answer is 56 pC, as stated in the textbook. The confusion arose from using an incorrect formula format. The conversation emphasizes the importance of using the standard formula for accurate calculations in electrostatics.
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Homework Statement


what is the magnitude or a point charge whose electric field 50cm away has the magnitude 2nc?


Homework Equations


E=1/4pi.epsilon sub zero q absolute/r sqrt2
1/4pi.epsilon sub zero=8.99x10sqrt9

The Attempt at a Solution


that gives me 71.92 and my solution in the book says 56pC am I wrong?
 
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Yup, you're wrong :smile: The book's answer looks good.

Your formulas look a little odd. The field due to a point charge q at distance r is given by:

E = \frac{1}{4 \pi \epsilon_0} \frac{q}{r^2}

Often the initial constant constants are rolled into a single one, k, so that

E = k \frac{q}{r^2}

where k = 8.988 x 109 m/F
 
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