Deriving the damped circuit equation and energy dissipated through a resistor.

AI Thread Summary
The discussion focuses on deriving the damped circuit equation and calculating energy dissipation in a resistor during capacitor discharge. The energy stored in a capacitor is given as 0.5CE^2, and the instantaneous power dissipated through a resistor R during discharge is questioned. The equation E=R dq/dt + q/C is presented, with the goal of showing that the solution is q(t)=EC(1-e^(-t/RC)). Calculus is required for both problems, and there is a sense of frustration regarding the complexity of the questions in relation to the exam preparation. The thread emphasizes the challenge of understanding the derivation of the exponential function in the context of circuit analysis.
LogicX
Messages
175
Reaction score
1

Homework Statement



I figure I will just combine these two questions into one topic.

1) The energy stored in a capacitor is .5CE^2, where E is the voltage. Wat is the instantaneous power dissipated in a resistor R through which this capacitor discharges? Show that the total energy dissipated through the resistor is exactly .5CE^2

2) E=R dq/dt + q/C Show that the solution to this equation is q(t)=EC (1-e^(-t/RC))

Homework Equations



I=dq/dt=-Q/RC e^(-t/RC)

Voltage across a resistor in a series RC circuit: V=Ee^(-t/RC)

Both problems require calculus.

The Attempt at a Solution



For number 1... P=i^2 R ? I'm not sure what to do with this.

The second question I am just totally clueless about. I've never seen a derivative taken where you end up with e when you didn't start with e. I think this may be another example of "hey, we are going to give you this question to struggle with even though you have never learned the math. Good luck on the exam."

This is my last ditch attempt before my exam tomorrow.
 
Last edited:
Physics news on Phys.org
I'll write the solution for 2) as you say it's out of your reach.

E=R \ dq/dt + q/C

E - {q \over C} = R \ {dq \over dt}

dt = R \ {dq \over (E - {q \over C})}

\int_0^{\infty} {dt} = \int_0^{\infty} R\ { dq \over {(E - {q \over C}) } }

t = -{RC} \ ln {(E - {q \over C})} +K

Then with some passages you arrive to the final solution.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top