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Given that
\zeta (2n)=\frac{{\pi}^{2n}}{m}
Then how do you find m with respect to n where n is a natural number.
For
n=1, m=6
n=2, m=90
n=3, m=945
n=4, m=9450
n=5, m=93555
n=6, m=\frac{638512875}{691}
n=7, m=\frac{18243225}{2}
n=8, m=\frac{325641566250}{3617}
n=9, m=\frac{38979295480125}{43867}
n=10, m=\frac{1531329465290625}{174611}
But I don't see any pattern.
Thanks.
\zeta (2n)=\frac{{\pi}^{2n}}{m}
Then how do you find m with respect to n where n is a natural number.
For
n=1, m=6
n=2, m=90
n=3, m=945
n=4, m=9450
n=5, m=93555
n=6, m=\frac{638512875}{691}
n=7, m=\frac{18243225}{2}
n=8, m=\frac{325641566250}{3617}
n=9, m=\frac{38979295480125}{43867}
n=10, m=\frac{1531329465290625}{174611}
But I don't see any pattern.
Thanks.