Derive the displacements movable pulleys.

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The discussion focuses on deriving the accelerations of two masses in a movable pulley system. The initial reasoning involves analyzing the movement of the masses and pulleys, leading to the conclusion that the acceleration of mass M is 3a while the acceleration of mass 2M is a. The key insight is that as mass 2M moves up by x, it affects the lengths of the strings, resulting in a 3:1 acceleration ratio. The participants confirm the correctness of this reasoning, emphasizing the relationship between the movements of the blocks and pulleys. The final consensus validates the derived accelerations based on the displacement constraints.
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Homework Statement


Obtain the accelerations of mass a and mass b.



Homework Equations


Once i derive the displacement relation constraint, then i just have to diff twice w.r.t time. This part is ok.


The Attempt at a Solution


I am trying to reason this way: suppose 2M moves up by x. Following the right string of 2M to pulley2 then to pulley 1 = This means pulley1 move down by x. Following the left string of 2M to pulley1 = this causes M to move down by x. So M moves by 2x. the acc of m must be 2a and acc of 2m is a. but the answer is m acc at 3a and 2m acc at a.
 

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The right piece of the left string gets shorter by 2x when the block B rises by x, as the left pulley descends by x. So the left block moves down by 2x with respect to the left pulley.

ehild
 
Ok, I'm getting it. The right piece of left string gets shorter by 2x meaning that the left piece of the right string must increase by 2x thus left block moves 2x w.r.t left pulley. Since left pulley is moving at dist x w.r.t right pulley. left block is moving 3x wrt right pulley. this explains the 3:1 acc ratio. Am I right.
Thanks
 
It is right now.

ehild
 
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