Why Does an Atwood's Machine Behave as It Does?

  • Thread starter Thread starter Leilei
  • Start date Start date
  • Tags Tags
    Machine
AI Thread Summary
In the discussion about Atwood's machine, the user seeks clarification on the behavior of two equal masses suspended over a pulley. It is confirmed that the masses will stop moving when they reach equilibrium, as the forces acting on them are balanced. When mass is shifted from one side to the other, the acceleration increases due to the heavier side exerting greater force. However, if the total mass on both sides increases while maintaining the mass difference, the acceleration decreases because the net force is reduced. The user is reassured that both masses experience the same acceleration due to the equal tension in the connecting string.
Leilei
Okay, I had to do a problem concerning the Atwoods machine over the weekend. I'm not doing very well in Physics right now, and I don't have any friends in that class, so I thankfully found this place. I have already tried thinking about these problems...

1. If two objects of equal mass are suspended from either end of a string passing over a light pulley (an Atwood's machine), what lind of motion do you expect to occur? Why?

I said that if the two objects of equal masss are suspended over a light pulley, the objects will move only until they are both at wqual distances from the ground. Then they will not move at all.

But the part I'm stuck on is -- why? Why does this occur? How can I explain this correctly?

2. For an Atwood's machine, how would you expect the acceleration to change if you:

- Move mass from one side to the other, keeping the total mass constant?

I'm not sure if this is correct: I said, the acceleration would increase. The mass of one side is gerater than the mass of the other, meaning the heaver side has a greater weight force (mg) acting upon it equating to a greater accelearation.

- How about if you gradually increase the mass of both sides, keeping the difference in mass constant?
I said the acceleration will remain the same because ratio of masses are equal. I am not sure if this is correct either.

3. Why do the two masses have the same acceleration?
I said the two masses have the same acceleration because the tension throughout the string is equal. The combined mass pulls each other at the same rate becauseb oth have the same foreces acting upon them.

I'm not sure at all if any of my answers are correct. What I need the most help on is #1. If somebody could help me, I would appreciate it very much.
 
Physics news on Phys.org
Please do not post the same question on two different forums.
 



Hi there,

First of all, don't worry, it's completely normal to struggle with physics and it's great that you're seeking help! Let's go through your answers and see if we can clarify things for you.

1. Your answer is correct! The reason why the objects will eventually stop moving is because they reach a state of equilibrium where the tension in the string is equal on both sides, meaning the forces on both sides are balanced. This is also known as the "principle of moments" or "principle of balanced forces". In simpler terms, the objects will stop moving because there is no net force acting on them.

2. Your answer for the first part is correct. When you move mass from one side to the other, the heavier side will have a greater weight force and thus a greater acceleration. For the second part, your answer is not quite correct. The acceleration will actually decrease as the total mass increases, because the weight force (mg) is also increasing. This means that the net force and thus the acceleration, which is directly proportional to the net force, will decrease.

3. Your answer is correct! The reason why the two masses have the same acceleration is because they are connected by the same string and thus experience the same tension force. This tension force is what causes the acceleration, and since it is equal on both sides, the acceleration will also be equal.

I hope this helps clarify things for you. Keep practicing and seeking help when needed, and you'll do great in your physics class!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top