How do I find the velocity that an electron must acquire

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To find the velocity an electron must acquire to equal the rest mass of a proton, the relevant formula is m = m_0 / (1 - v^2/c^2)^(1/2). The mass of the electron is approximately 1/1836 that of the proton. By rearranging the formula, the velocity can be expressed as v = (√(1836^2 - 1) / 1836) c. This calculation reveals that the required velocity is nearly equal to the speed of light. The discussion highlights the importance of special relativity in understanding these mass and velocity relationships.
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How do I find the velocity that an electron must acquire, if its mass is to be equal to the rest mass of a proton?

I know that the masses of electron and proton are 9.11 X 10^-31 kg and 1.67 X 10^-27 kg, respectively.

Am I going to use the formula m = m_0 / (1 - v^2/c^2)^(1/2) ?

How do I continue from here?
 
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irony of truth said:
How do I find the velocity that an electron must acquire, if its mass is to be equal to the rest mass of a proton?

I know that the masses of electron and proton are 9.11 X 10^-31 kg and 1.67 X 10^-27 kg, respectively.

Am I going to use the formula m = m_0 / (1 - v^2/c^2)^(1/2) ?

How do I continue from here?

Let's approximate this number,okay??
\frac{9.11\cdot 10^{-31}}{1.67\cdot 10^{-27}}\sim \frac{1}{1836}

I'll give u the final answer and let u work out your way through to it.
v=\frac{\sqrt{1836^{2}-1}}{1836} c

Good luck!
 
Hmm, I just got your reply.. seems like it is almost the same as the speed of light... amazing!
 
irony of truth said:
Hmm, I just got your reply.. seems like it is almost the same as the speed of light... amazing!

Judging it in the context of SR,it's not surprising,let alone amazing.So,by "I just got your reply" does it mean you solved the problem and confronted the result with mine ??Hopefully so,it would mean that the PF community did its job and got u happy and satisfied... :approve: :approve:
 
So,by "I just got your reply" does it mean you solved the problem and confronted the result with mine ??

Hi! What I mean is that when I saw your hints, I quickly solve the problem - knowing that my first idea is correct... but I did not confront your answer... I just saw that I got the correct solution.. same as yours.

But I thank you for helping me.
 
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