How many of a note can we hear problem

  • Thread starter Thread starter AlaskanPow
  • Start date Start date
AI Thread Summary
The highest note on the saxophone is 1,568 Hz, and the maximum frequency humans can hear is 20,000 Hz. To determine how many harmonics of the saxophone note can be heard, one can divide 20,000 Hz by 1,568 Hz, resulting in 12 harmonics. Rounding up would exceed the audible range, which is why rounding down is necessary. The discussion emphasizes the importance of understanding harmonic frequencies in relation to human hearing limits.
AlaskanPow
Messages
13
Reaction score
0
The frequency of the highest note on the saxophone is 1,568 Hz.
1. How many harmonics of that note can we hear?
2. How many harmonics of the note one octave below it can we hear?

The book really gives no examples or information on determining number of harmonics, so an explanation of the problem would be great.
 
Physics news on Phys.org
AlaskanPow said:
The frequency of the highest note on the saxophone is 1,568 Hz.
1. How many harmonics of that note can we hear?
2. How many harmonics of the note one octave below it can we hear?

The book really gives no examples or information on determining number of harmonics, so an explanation of the problem would be great.
Hello AlaskanPow. Welcome to PF !

What's the highest frequency that a human can hear?
 
20,000 Hz according to my book. Do we do this then ----> 20000Hz/1568Hz?
 
Last edited:
AlaskanPow said:
20,000 Hz according to my book. Do we do this then ----> 20000Hz/1568Hz?
No.

How many times can you double 1568Hz without exceeding 20000Hz ?
 
Well i did the 20000Hz/1568Hz and it gave me the right answer of 12 harmonics. I am not sure why it rounded down like that though.
 
AlaskanPow said:
Well i did the 20000Hz/1568Hz and it gave me the right answer of 12 harmonics. I am not sure why it rounded down like that though.

I had a brain cramp.

Of course 20000Hz/1568Hz is correct.

If you round up, the highest harmonic is grater than 20000Hz .
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top