1. The air in a closed pipe with an adjustable plunger in is made to vibrate at a frequency 256 Hz over its open end. As the length of the pipe is increased, loud notes are heard as the standing wave in the pipe resonates with the tuning fork. (a) What is the shortest length that will cause a loud note? (b) If the pipe is 1.5 m long, how many loud notes will you hear as the plunger is withdrawn? 2. Relevant formulae are For closed pipe, first harmonic λ = 4L , f¹ = v/4L f³ = 3v/4L = 3 * f¹ 3. Answers (a) Rearranging the formula to get: L = v/4f¹ L = 330/4*256 L = 330/1024 L = 0.32m or 32.2cm (b) i thinking that i need to look for the 3rd and 5th harmonics to see how the length I'd affected but i calculate this to be smaller and therefore not really affected by a longer tube! Help?