Ping Pong Ball Projectile Launcher

AI Thread Summary
The discussion focuses on creating a ping pong ball projectile launcher using specified materials, including cardboard, paper towel tubes, popsicle sticks, rubber bands, and paper clips. The launcher must be designed to launch a standard 38 mm ping pong ball from a desk height of 76.5 cm. Participants seek basic ideas and guidelines for building the launcher effectively. A suggested resource for design inspiration is provided, linking to a Khan Academy project. Overall, the conversation emphasizes the need for creative solutions within the material constraints.
vania1711
Messages
1
Reaction score
0
Allowed materials:
-1 sheet of 8"x8" cardboard to be used as the base
-another sheet of 8"x8" cardboard (that may be cut)
-2 standard paper towel tubes
-10 standard popsicle sticks
-up to 10 rubber bands (maximum unstretched length is 10 cm)
-5 standard paper clips (max length 5 cm each)
- tape/glue**The projectile will be a standard, 38 mm, ping-pong ball and must be launched to long distances from a desk with a height of 76.5 cm (30 in)

I really need help with this please just give me some basic ideas on where to start or some guidelines! thank you!
 
Physics news on Phys.org
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top