Spring force and the period of it's ocilation

AI Thread Summary
The discussion focuses on calculating the period of oscillation for a mass attached to a vertical spring, where the spring stretches 5.8 cm from its equilibrium position. The key equations involved include T = 2(pi)sqrt(m/k) for the period and k = mg/d for spring constant determination. Participants are encouraged to find the spring constant (k) using the weight of the mass (mg) and the distance the spring stretches (5.8 cm). The conversation emphasizes understanding the relationship between mass, spring constant, and oscillation period. Overall, the thread provides insights into solving oscillation problems involving springs.
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1.A mass is attached to a vertical spring, which then goes into oscillation.
At the high point of the oscillation, the spring is in the
original unstretched equilibrium position it had before the mass
was attached; the low point is 5.8 cm below this. Find the oscillation
period.




Homework Equations


sin(α+ or -β)
sqrt(k/m)= ω


The Attempt at a Solution


having the half of 5.8cm
2.9cm k = mg
 
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Think about this

T = 2(pi)sqrt(m/k)

How do you find k?

(force) (distance) = k and force in this case is mg

These are enough clues.
 
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