Find the magnitude and the direction of the electric field at the thir

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SUMMARY

The discussion focuses on calculating the electric field at the third corner of a triangle formed by two point charges, specifically q1 = -11.3 μC and q2 = 15.4 μC. The correct magnitude of the electric field is determined to be 1.07e+07 N/C at an angle of 71.2 degrees above the -x-axis. Participants emphasized the importance of unit conversion and the impact of charge signs on the direction of the electric field. Miscalculations were attributed to incorrect unit conversions, particularly between microcoulombs and centimeters.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with unit conversions, specifically between microcoulombs (μC) and coulombs (C)
  • Knowledge of vector components in physics
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Review Coulomb's Law and its applications in electric field calculations
  • Learn about vector addition and decomposition in physics
  • Study unit conversion techniques, especially for electrical units
  • Explore the concept of electric field direction and its dependence on charge signs
USEFUL FOR

Students in physics courses, particularly those studying electrostatics, as well as educators and anyone needing to understand electric field calculations involving point charges.

Richard Ros
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Homework Statement


Two point charges are placed at two of the corners of a triangle as shown in the figure. (Take q1 = -11.3 μC, and q2 = 15.4 μC.) Find the magnitude and the direction of the electric field at the third corner of the triangle. {Correct Answer: 1.07e+07 N/C at 71.2 degrees above the -x-axis}


Homework Equations


F = ((1)/(4πε0))(q1*q2/r^2)

The Attempt at a Solution


Attached files. What am i doing wrong? I can't seem to get the correct answer.
 

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Did you convert units correctly? Your answers appear to be off by some factors of 10.

Is Ey from q1 positive or negative? [Edited]
 
Hmm I don't know how I got a negative. But either way when I solve for the magnitude it'll end up being positive. Which unit should I convert? The μc or cm?
 
Richard Ros said:
Hmm I don't know how I got a negative. But either way when I solve for the magnitude it'll end up being positive.
Yes, but the sign of Ey will affect the answer for the direction angle.
Which unit should I convert? The μc or cm?
Neither μC nor cm is an SI unit.
 
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Thanks, turns out it was just my conversion.
 

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