Find the magnitude and the direction of the electric field at the thir

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Homework Help Overview

The problem involves calculating the electric field at a corner of a triangle formed by two point charges, with specific values given for the charges. The original poster attempts to find both the magnitude and direction of the electric field at the third corner.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss unit conversions and their impact on the calculations, questioning whether the original poster converted the charge and distance units correctly. There is also a focus on the sign of the electric field component and its effect on direction.

Discussion Status

The discussion is ongoing, with some participants providing guidance on unit conversion and the implications of negative values on direction. The original poster acknowledges a mistake in conversion, indicating a potential path forward.

Contextual Notes

There is mention of non-SI units being used, which may affect the calculations. The original poster's confusion about the sign of the electric field component suggests a need for clarification on the underlying principles of electric fields.

Richard Ros
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Homework Statement


Two point charges are placed at two of the corners of a triangle as shown in the figure. (Take q1 = -11.3 μC, and q2 = 15.4 μC.) Find the magnitude and the direction of the electric field at the third corner of the triangle. {Correct Answer: 1.07e+07 N/C at 71.2 degrees above the -x-axis}


Homework Equations


F = ((1)/(4πε0))(q1*q2/r^2)

The Attempt at a Solution


Attached files. What am i doing wrong? I can't seem to get the correct answer.
 

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Last edited:
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Did you convert units correctly? Your answers appear to be off by some factors of 10.

Is Ey from q1 positive or negative? [Edited]
 
Hmm I don't know how I got a negative. But either way when I solve for the magnitude it'll end up being positive. Which unit should I convert? The μc or cm?
 
Richard Ros said:
Hmm I don't know how I got a negative. But either way when I solve for the magnitude it'll end up being positive.
Yes, but the sign of Ey will affect the answer for the direction angle.
Which unit should I convert? The μc or cm?
Neither μC nor cm is an SI unit.
 
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Thanks, turns out it was just my conversion.
 

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