Impedance of practical Capacitor

AI Thread Summary
The discussion focuses on calculating the impedance of a practical capacitor modeled as an ideal capacitor in parallel with a resistor at a specific frequency. The user initially computes the impedance but finds a discrepancy between their result and the book's solution, particularly in the angle measurement. It is suggested that the error arises from using the wrong angle unit, as the user was in degree mode instead of radians. After clarification, it is confirmed that the correct angle in radians aligns with the book's answer. The discussion emphasizes the importance of ensuring the correct mode for trigonometric calculations in impedance analysis.
bigu01
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Homework Statement


A practical capacitor can be modeled by an ideal capacitor in parallel with a resistor.Find the impedance of practical capacitor at the radian frequency ω=377rad/s.Known C1=0.1 x 10^-6F R1=1 *10^6.

Homework Equations



1/Z=1/R1 + jCω

The Attempt at a Solution

I am first determining the Z, by adding the impedance of resistor and the capacitor in parallel.
And I am getting Z1(377)=10^6/(1+j37.7)= 2.6516*10^4 ∠-1.519 However book solutions gives ∠-1.5443.I would like to get some help about where my mistake is,or how should I approach the question. I know that finding the angle we should do θ=arctan(y/x) where y is the imaginary part and x is the real part.Hope I was clear and did not complicate it.
 
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Please show your reasoning and working.
 
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R//C Z=R//1/jωC = R1/(1+jωC1R1) inputing numbers I get =10^6/(1+j37.7) multiplying by 1+j37.7's conjugate I got 703.09-26506.54j , tried to find the length got the 26515.86 , finding the angle theta=arctan(-26506.54/703.09) doesn't give me same as book result. I get -1.519 book got -1.5443
 
Looking at my procedure everything looks fine.I am wondering if book has done any mistake,or there is something else I should do, which I have missed,and it is making me do the mistake.
 
bigu01 said:
R//C Z=R//1/jωC = R1/(1+jωC1R1) inputing numbers I get =10^6/(1+j37.7) multiplying by 1+j37.7's conjugate I got 703.09-26506.54j , tried to find the length got the 26515.86 , finding the angle theta=arctan(-26506.54/703.09) doesn't give me same as book result. I get -1.519 book got -1.5443

Your numbers all look fine except for the result of the arctan(). When I enter that argument and take the arctan I get the book's result.
 
gneill said:
Your numbers all look fine except for the result of the arctan(). When I enter that argument and take the arctan I get the book's result.

You're saying that arctan(26506.54/703.09) gives 1.554 , either my two calculators are wrong or I am doing something wrong.
 
bigu01 said:
You're saying that arctan(26506.54/703.09) gives 1.554 , either my two calculators are wrong or I am doing something wrong.

That's what I'm saying :smile:
 
Okay then, what about this one 101.92+j90.38,what do you get as your ∠? The book answer is ∠0.723 and about this one I have no clue how did they get it
 
bigu01 said:
Okay then, what about this one 101.92+j90.38,what do you get as your ∠? The book answer is ∠0.723 and about this one I have no clue how did they get it

The numbers are probably rounded somewhat. I get 0.725 radians as the angle.
 
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Multiple threads are confusing... it looks like the error was here:
bigu01 said:
I was using the degree mode, I should have used the radian angle unit one

I have no idea how you get -1.519 in degree mode... well does not matter.
 

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