Hmm, I know in a vacuum that with projectile motion

[schattenjaeger]

shooting the projectile at 45 degrees will yield the greatest distance, and 30 and 60 degrees should go the same distance, but if you add in an air-friction force of -kv^2 (where k is .05 and v is the instant speed)is it possible for that to be otherwise?

'cuz the program I just wrote says it is, and I'm thinking I might've screwed up the program. If that's the case, anyone here good at FORTRAN?

 

[James R]

There's no reason to suppose that, with air resistance, a projectile fired at 30 or 60 degrees will go the same distance.

 

[OlderDan]

shooting the projectile at 45 degrees will yield the greatest distance, and 30 and 60 degrees should go the same distance, but if you add in an air-friction force of -kv^2 (where k is .05 and v is the instant speed)is it possible for that to be otherwise?

'cuz the program I just wrote says it is, and I'm thinking I might've screwed up the program. If that's the case, anyone here good at FORTRAN?

There's no reason to suppose that, with air resistance, a projectile fired at 30 or 60 degrees will go the same distance.

or that one fired at 45 degrees will have the greatest distance.

I used to know some FORTRAN, but even that has probably changed since I last did any. How are you approaching the problem?

 

[whozum]

If you assume a uniform air field then the magnitudes of a 30 and 60 degree launch will decrease the same.