Kinematics Questions: Acceleration, Velocity, and the Speed of Light

AI Thread Summary
The discussion addresses several kinematics questions, focusing on acceleration and velocity calculations. The first question involves calculating the time required for an object accelerating at 9.8 m/s² to reach 10% of the speed of light, resulting in approximately 849.8 hours. The second question about an object uniformly accelerated at 4 m/s² seeks clarification on the time frame for determining velocity before and after reaching 50 m/s. The third question calculates the average acceleration of a dragster that reaches 632 km/h in 3.72 seconds, yielding an acceleration of 47.2 m/s². Overall, the solutions provided are confirmed as correct, with a request for clarification on the second question.
Physicsrapper
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Hi, I have some questions regarding Kinematics:

1. If an object is accelerating at 9.8 m/s^2, how much time does it Need to reach ten percent of the Speed of light?

Speed of light: 299 792 458 m / s -> 10% -> 299 792 45,8 m / s

t = v/a -> 299 792 45,8 m / s / 9.8 m/s^2 = 3 059 106.714 s = 849.8 h


2. An object is uniformly accelerated at a = 4m/s^2. At time t, the object has a velocity v = 50 m/s. What is its velocity before and afterwards?

t = v/a = 50m/s / 4m/s^2 = 12.5 s

7.5s * 4m/s^2 = 30 m/s
17.5 s * 4m/s^2 = 70 m/s

3. The fastest dragster reaches 632 km/h in 3.72s. Find its average acceleration.

a=v/t -> 175.6m/s / 3.72s = 47.2m/s^2


Are all my Solutions true?
 
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Physicsrapper said:
Hi, I have some questions regarding Kinematics:

1. If an object is accelerating at 9.8 m/s^2, how much time does it Need to reach ten percent of the Speed of light?

Speed of light: 299 792 458 m / s -> 10% -> 299 792 45,8 m / s

t = v/a -> 299 792 45,8 m / s / 9.8 m/s^2 = 3 059 106.714 s = 849.8 h
Correct
Physicsrapper said:
2. An object is uniformly accelerated at a = 4m/s^2. At time t, the object has a velocity v = 50 m/s. What is its velocity before and afterwards?
This question does not make much sense to me. What do you mean by before? How many seconds before? Howmany seconds afterwards?
Physicsrapper said:
3. The fastest dragster reaches 632 km/h in 3.72s. Find its average acceleration.

a=v/t -> 175.6m/s / 3.72s = 47.2m/s^2
Correct
 
This question does not make much sense to me. What do you mean by before? How many seconds before? Howmany seconds afterwards?

Sorry, it's 5s.
Thank you for the correction!
 
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