Why Is My Line Integral Calculation Incorrect?

[asdf1]

Calculate the line integral of the function v=(y的平方, 2x(y+1), 0) from the
point a=(1,0,0) to the point b=(2,2,0)
The correct Ans: 11

However, when I was calculuating the problem,
I supposed(is that the right word?) to make the parameter equations,

x=1+t
y=1+t
z=0
where 0<t<1
but when I integrated the function, the answer is 6.

 

[mantito]

i don't know why, but i see your function as some chinese characters, can you retype it in some other way:).

 

[TD]

Are you sure about that parametrization of your path?

I'd say

\left\{ \begin{array}{l}<br /> x = t \\ <br /> y = 2t - 2 \\ <br /> z = 0 \\ <br /> \end{array} \right

or

\left\{ \begin{array}{l}<br /> x = t + 1 \\ <br /> y = 2t \\ <br /> z = 0 \\ <br /> \end{array} \right

 

[HallsofIvy]

Calculate the line integral of the function v=(y的平方, 2x(y+1), 0) from the
point a=(1,0,0) to the point b=(2,2,0)
The correct Ans: 11

However, when I was calculuating the problem,
I supposed(is that the right word?) to make the parameter equations,

x=1+t
y=1+t
z=0
where 0<t<1
but when I integrated the function, the answer is 6.

when t= 0, your parametrization gives (1, 1, 0), there is no value of t that gives (1, 0, 0).

 

[asdf1]

sorry, i mistyped~
a=(1,0,0)