Relative Velocity and Vector Resolution

AI Thread Summary
The discussion centers on calculating the velocity of a boat relative to the shore while rowing in a river with a current. The velocity of the boat relative to the shore is determined to be 5 m/s, forming a 3-4-5 triangle. For the components of velocity, the parallel component to the shore is 3 m/s (the river's current), while the perpendicular component is 4 m/s (the boat's speed). Participants confirm that using the triangle helps clarify these components. The calculations illustrate the relationship between the boat's movement and the river's flow.
Jacobpm64
Messages
235
Reaction score
0
You row a boat perpendicular to the shore of a river that flows at 3.0 m/s. The velocity of your boat is 4.0 m/s relative to the water.
a. What is your velocity of your boat relative to the shore?
b. What is the component of your velocity parallel to the shore? Perpendicular to it?
A was very easy... If you draw it out, you can easily see that it's a 3,4,5 triangle, so the answer to A is 5 m/s.
I'm not sure how to work out B. Which number do I use to find the components? Would the parallel to the shore component be 4 m/s? Would the perpendicular be 3 m/s? I'm not sure.. Or is it totally different numbers? Help with part B please.
 
Physics news on Phys.org
You can use the same triangle that you drew for A to work out the components for B. It's easier than you think.
 
ok, which sides am i using of the triangle? it's a 3,4,5 triangle. Am i correct in saying that the velocity component parallel to the shore is the velocity of the river (+3 m/s --- since it is flowing parallel to the shore) and the velocity component perpendicular to the shore is the velocity of the boat relative to the river (+4 m/s --- since the boat is moving in a direction perpendicular to the shore)?
 
Sounds good to me.
 
thanks a lot
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top