How many years would it take for the glacier to move .74km?

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A glacier moves at a speed of 41 nanometers per second, which converts to approximately 4.1 x 10^-11 kilometers per second. To determine how long it would take for the glacier to move 0.74 kilometers, the time is calculated using the formula t = d/v. This results in a time of about 5013550.136 hours, which is roughly 572 years. The calculations highlight the extremely slow movement of glaciers over time.
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omg help!

ok ppl I am having trouble with this problem...

A glacier moves with a speed of 41 nm/s. How many years would it take for the glacier to move .74km? answer in units of yr.

ok and this is what I've done...

i changed 41 nm to km which i got as 41*10^-6 ...

and then i divided it by 0.74 and got some weird number like 31536000

ur somebody please tell me how to do it
 
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first of all, a nanometer is 10^-12 kilometers

so the velocity would actually be 4.1*10^-11 km/s

now we convert this into km/h, so:

(4.1*10^-11)*3600 = 1.476*10^-7 km/h

now to get time it would take, we obviously use t = d/v:

t = (0.74)/(1.476*10^-7)

t = 5013550.136 hours

which is approximately 572 years
 
thanks so much u basically helped me through half of my homework! u guyz are awesome at this site!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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