1) Find the global max and min values of the function
f(x,y)=x/[x2+(y-1)2+4] on the first quadrant S={(x,y)|x,y>0}
Solution: (from textbook example)
f(x,y)>0 on S and f(0,y)=0, so the minimum is zero.
Moreover, f(x,y) is less than the smaller of 1/x and 1/(y-1)2, so f vanishes as...