$Rectangle\,\,ABCD\,\,given\,\, point \,\,E,F \,\,on \,\,\overline {BC},\overline {AB}\,\,\, respectively$
$if \,\,\overline{BF}=\overline{CE}=4,\overline{BE}=2,point \,\, P \,\,is\,\, the \,\, intersection\,\ of\,\,\overline{AE}\,\,and\,\,\overline{CF},\,\, and \,\, \angle APC=\angle AEB+\angle...