Hello,
Could someone please help me simplify the equation:
\frac{-1}{(c1+c2)} \cdot ln [(m1-m2)g-(c1+c2)v] = \frac{t}{(m1+m2)} - \frac{1}{(c1+c2)} \cdot ln[(m1-m2)g]
(where c1, c2, m1, m2, g, are constants)
so as to get: v = \frac{(m1-m2)g}{(c1+c2)} \cdot [ 1 - exp[\frac{-(c1+c2)t...