At my fixed point of (1,1), I should have a stable spiral but I keep getting analytically that it is a saddle.
$$
\begin{cases} \dot{x} = x(3 - 2x - y)\\
\dot{y} = y(-5 + 5x)
\end{cases}
$$
The fixed points are $(0,0)$, $\left(\frac{3}{2},0\right)$, and $\left(1,1\right)$.
Also, the Jacobian...