2nd year Calculus: partial derivatives

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Homework Help Overview

The discussion revolves around the topic of partial derivatives in the context of a calculus problem involving a function of multiple variables. The original poster expresses uncertainty about how to begin solving the problem, which involves demonstrating a relationship between second derivatives with respect to different variables.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to clarify the problem statement and suggest using LaTeX for better communication. The original poster attempts to express the relationship between second derivatives and seeks guidance on applying the chain rule for multivariable functions. There are questions about the correctness of the derived second derivatives and how to compute them with respect to different variables.

Discussion Status

The discussion is ongoing, with participants providing hints about the chain rule and questioning the original poster's calculations. Some guidance has been offered regarding the approach to take, but there is no explicit consensus on the correctness of the attempts made so far.

Contextual Notes

There is mention of an attached image that contains the problem statement, which is not visible to all participants. The original poster's understanding of the chain rule and its application to the problem is under discussion, indicating potential gaps in knowledge that are being explored.

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Homework Statement


See attatched image.

Homework Equations


I just don't know where to start...


The Attempt at a Solution


Any help would be appreciated! :)
 

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images don't clear for a while, try writing the problem for a quicker reply

there's tips on using tex floating around or just click on other etex to see how its written
 
If u=f(x,y), where x=escos(t) and y=essin(t), show that:
second derivative of u wrt x + second derivative of u wrt y = e-2s(second derivative of u wrt s + second derivative of u wrt t)
 
Is this the question?
[tex]\frac{\partial^2u}{\partial x^2} + \frac{\partial^2u}{\partial y^2}[/tex]
[tex]=~e^{-2s}(\frac{\partial^2u}{\partial s^2} + \frac{\partial^2u}{\partial t^2})[/tex]

Do you know the form of the chain rule for multivariable functions? If so, start by taking the partials of u w. r. t. x and y, and then take the partials of the first with respect to x and of the second with respect to y, then add them together.
 
Ok, well I got :
[tex]\frac{\partial^2u}{\partial x^2}[/tex] =-2essin(t) and

[tex]\frac{\partial^2u}{\partial y^2}[/tex] = 2escos(t)
 
So what do you get for
[tex]\frac{\partial^2u}{\partial s^2}[/tex]
and
[tex]\frac{\partial^2u}{\partial t^2}[/tex]
 
well, from the formula,
[tex](\frac{\partial^2u}{\partial s^2} + \frac{\partial^2u}{\partial t^2})[/tex] should = 2e3s(cos(t) - sin(t))
But I still don't understant how to get to the partails wrt s and t
I have u=f(x,y) so u=f(escost,essin t)
 
So u is a function of x and y, and x and y are each functions of s and t. Here's the form of the chain rule for one of the partials you need.

[tex]\frac{\partial u}{\partial s}~=~\frac{\partial u}{\partial x}\frac{\partial x}{\partial s} + \frac{\partial u}{\partial y}\frac{\partial y}{\partial s}[/tex]

The other partial derivative is very similar, but any partial with respect to s should be with respect to t.
 
Ok, well when I tried to do that I got answerd without sin and cos in them.. is what i did so far right?
and is there a formula for finding the second partials wrt s and t?
 

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