What would be the energy eigenvalues of this particle?

AI Thread Summary
The discussion centers on determining the energy eigenvalues of a particle confined in a 3D box with dimensions L, 2L, and 2L. The initial assumption presented was that the energy eigenvalues could be expressed as hcross*w*A. However, a participant corrected this by providing the accurate formula for the energy eigenvalues, which is (h^2/8m)(n_1^2/L^2 + n_2^2/4L^2 + n_3^2/4L^2), where n_1, n_2, and n_3 are quantum numbers. The original poster expressed gratitude for the clarification. The thread effectively highlights the importance of precise calculations in quantum mechanics.
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howdy all,
i need some answers if possible
suppose i have a particle mass m, confinded in a 3d box sides L,2L,2L
what would be the energy eigenvalues of this particle
i presumed it to be:

hcross*w*A
where hcross is h/2*pi
w is omega
and A is the 'amplitude' of the wavefunction.
can someone confirm this or tell what it may actually be
thanks
peace
 
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Your answer is not correct, the correct answer should be.
\frac{h^2}{8m}(\frac{n_1^2}{L^2}+\frac{n_2^2}{4L^2}+\frac{n_3^2}{4L^2}),
n_1=1,2..., n_2, n_3 are the same.
 
Last edited:
hey thanks heaps for your help brother
peace
 

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