A 63-kg student stands on a 34-kg cart that is free to move

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A 63-kg student on a 34-kg cart is initially moving at 3.2 m/s west. When the student walks at 1.8 m/s at an angle of 25° west of north, the momentum of the system must be conserved to find the new velocity of the cart. The discussion highlights confusion regarding the direction of the student's movement and its impact on the cart's velocity. The conservation of momentum equation, p=mv, is essential for solving the problem. Understanding the vector components of the student's movement is crucial for accurately determining the cart's new velocity.
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Homework Statement


A 63-kg student stands on a 34-kg cart that is free to move in any direction. The cart and student are moving together with a velocity of 3.2 m/s [W]. The student then starts to walk so that her velocity is 1.8 m/s [25° W of N] relative to the floor. Calculate the new velocity of the cart.


Homework Equations


p=mv


The Attempt at a Solution


i don't know what is going on
 

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jasonbans said:

Homework Statement


A 63-kg student stands on a 34-kg cart that is free to move in any direction. The cart and student are moving together with a velocity of 3.2 m/s [W]. The student then starts to walk so that her velocity is 1.8 m/s [25° W of N] relative to the floor. Calculate the new velocity of the cart.


Homework Equations


p=mv


The Attempt at a Solution


i don't know what is going on

why is the direction point to 25 degrees E of S
 
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