A ball is thrown up , another is dropped. Do they arrive at the same t

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Homework Help Overview

The problem involves two balls: one is thrown upwards and the other is dropped. The question posed is whether they arrive at the ground at the same time.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the initial conditions, such as the height from which each ball is released and the distances they travel. Some question the clarity of the question regarding where the balls are supposed to arrive.

Discussion Status

There are various interpretations of the problem, with some participants suggesting experimental verification while others explore the physics involved. Guidance has been offered regarding the equations of motion, but no consensus has been reached on the solution.

Contextual Notes

Participants note the assumption that both balls start from the same height and question the implications of the initial velocity of the thrown ball. There is also mention of the need for clarity on the term "arrive" in the context of the problem.

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Homework Statement



A ball is thrown up , another is dropped. Do they arrive at the same time?


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The Attempt at a Solution



I think they won't because the ball which is thrown up has a greater distance to travel, but I am not sure, can someone explain please?
 
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Arrive where?
 
the ground of course..
 
If I get the question right, you should do the following;

Assume that the current height of the balls is x. The first one is thrown up whereas the second is dropped. Distance the second ball travels can be found by using the following equation ; x=x0 + V0.t + 1/2at²

Now, let's say the first ball will go h higher hence the total distance travels is 2h+x. Now, you can do the same above equation and can find the total time.

Hope, I'm not mistaken.
 
Hey, what the, just get two balls and perform the experiment.
 
There is an easy way to look at the problem. The ball that is thrown upwards will eventually come to a halt at some height H. So in effect you have two balls that are being dropped from different heights...and one has a head start.
 

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