A body moving in a straight line with constant acceleration covers two successive distances of 1 meter in 3 seconds and 5 seconds. The problem can be approached by using the equation for distance, which incorporates initial velocity and acceleration. By setting up equations based on the distances covered in the specified time intervals, one can solve for the initial velocity and acceleration. The discussion emphasizes that the problem is straightforward once the correct approach is taken. The solution hinges on properly applying the kinematic equations for uniformly accelerated motion.
