A challenging friction and forces question

  • Thread starter Thread starter hibachii
  • Start date Start date
  • Tags Tags
    Forces Friction
Click For Summary

Homework Help Overview

The problem involves three objects connected by strings over a pulley system, with one object on a table and two hanging off the sides. The masses are specified, along with the coefficient of kinetic friction between the block on the table and the surface. Participants are tasked with drawing free-body diagrams, determining the acceleration of each object, and calculating the tensions in the cords, while also considering the effects of a smooth tabletop.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of force equations for each mass, with some confusion about the relationship between acceleration and the forces acting on the masses. There is debate over whether to set acceleration to zero and how to approach solving for multiple unknowns.

Discussion Status

The discussion is ongoing, with participants seeking clarification on how to write force equations and whether the acceleration is the same for all masses. Some guidance has been provided regarding the need to express Newton's second law for each mass separately, but there is still uncertainty about the correct approach.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also mention of a hypothetical scenario involving a smooth tabletop, prompting further questions about the effects on tension.

hibachii
Messages
17
Reaction score
0

Homework Statement



Three objects are connected on the table as shown in Figure P5.46 (a block of mass 1kg on a table is connected by two strings. The ends of the string each have a block hanging from it off the table, one of mass 4kg and one of mass 2kg. The strings are attached to a pulley system)
coefficient of kinetic friction between the block of mass m2
and the table is 0.350.
The objects have masses of m1
= 4.00 kg, m2
= 1.00 kg and m3
= 2.00 kg, and the
pulleys are frictionless. (a) Draw free-body diagrams of each of the objects. (b)
Determine the acceleration of each object and their directions. (c) Determine the
tensions in the two cords. What if? (d) If the tabletop were smooth, would the
tensions increase, decrease or stay the same? Explain.

Homework Equations



Figure P5.46 (in attachment)

The Attempt at a Solution



I have attempted a) and have no problem with it but it is b) and c) that is troubling me.
for b) i have written sum of all forces in the vertical direction is equal to 0(upwards positive). then i have input all the vertical forces for mass 1, T- mg=ma=0. I am stuck as i have two unknowns. please help!
 

Attachments

  • Untitled.png
    Untitled.png
    3.4 KB · Views: 807
Physics news on Phys.org
hibachii said:
for b) i have written sum of all forces in the vertical direction is equal to 0(upwards positive).
:confused:
then i have input all the vertical forces for mass 1, T- mg=ma=0. I am stuck as i have two unknowns.
Why are you setting the acceleration equal to zero?

Write separate force equations for each mass then solve together.
 
but then if i write separate force equations and solve together the acceleration would be the same for each mass wouldn't it? but it says to find acceleration of each mass. I am really confused :?
 
hibachii said:
but then if i write separate force equations and solve together the acceleration would be the same for each mass wouldn't it? but it says to find acceleration of each mass.
The masses are connected by the strings. They will all have the same acceleration (the same magnitude, but different directions, of course).
 
what are the force equations? i have no idea.
 
hibachii said:
what are the force equations? i have no idea.
Do the same thing you did for mass 1: Write equations expressing Newton's 2nd law. (Don't set the acceleration equal to zero, though.) Make sure you do part (a) first: you'll need to know the forces acting on each mass.
 

Similar threads

Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
16
Views
3K
  • · Replies 47 ·
2
Replies
47
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K