A LinAlg Proof Involving Orthogonal Complement

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    Orthogonal Proof
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Homework Statement



Here is the problem and my complete answer.

Am I OK?

Thanks!

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Homework Equations





The Attempt at a Solution


 
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No, it is not ok. You seem to prove that if u,v\in S^\bot, that cu+v is an element of S. But this is simply not true at all.
Likewise, you take a,b\in S^{\bot \bot} and you conclude that these are in S^\bot. But this is also not true.

In short, it is NOT true that

S^{\bot \bot}\subseteq S^\bot \subseteq S

How do you prove the theorem, well you need to prove two things:

1) S^{\bot \bot} is a subspace.
2) S\subseteq S^{\bot \bot}.
 
Thank you!

By the skin of my teeth, some help from you, and the grace of God, I received the best grade I could have expected in Linear Algebra.

Thanks, again!

Joe
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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