A LinAlg Proof Involving Orthogonal Complement

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SUMMARY

The discussion centers on a proof involving the orthogonal complement in Linear Algebra, specifically addressing the misconception that if vectors u and v belong to S⊥, then their linear combination cu + v is an element of S. This assertion is incorrect, as is the claim that elements a and b in S⊥⊥ are necessarily in S⊥. The correct theorem states that S⊥⊥ is a subspace and that S is a subset of S⊥⊥. The user Joe successfully navigated these concepts to achieve a commendable grade in his Linear Algebra course.

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  • Understanding of Linear Algebra concepts, particularly orthogonal complements.
  • Familiarity with subspace definitions and properties.
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  • Study the properties of orthogonal complements in vector spaces.
  • Learn how to prove that S⊥⊥ is a subspace.
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Students and educators in Linear Algebra, particularly those focusing on vector spaces and orthogonal complements, as well as anyone preparing for exams or assignments in this subject area.

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Homework Statement



Here is the problem and my complete answer.

Am I OK?

Thanks!

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Homework Equations





The Attempt at a Solution


 
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No, it is not ok. You seem to prove that if [itex]u,v\in S^\bot[/itex], that cu+v is an element of S. But this is simply not true at all.
Likewise, you take [itex]a,b\in S^{\bot \bot}[/itex] and you conclude that these are in [itex]S^\bot[/itex]. But this is also not true.

In short, it is NOT true that

[tex]S^{\bot \bot}\subseteq S^\bot \subseteq S[/tex]

How do you prove the theorem, well you need to prove two things:

1) [itex]S^{\bot \bot}[/itex] is a subspace.
2) [itex]S\subseteq S^{\bot \bot}[/itex].
 
Thank you!

By the skin of my teeth, some help from you, and the grace of God, I received the best grade I could have expected in Linear Algebra.

Thanks, again!

Joe
 

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