A person can focus objects clearly only between 15 cm and 40 cm.

  • Thread starter Thread starter greg_k92
  • Start date Start date
  • Tags Tags
    Focus
greg_k92
Messages
1
Reaction score
0

Homework Statement


A person can focus objects clearly only between 15 cm and 40 cm. What eyeglasses would you prescribe

Homework Equations


1/p+1/q=1/f
P=1/f

The Attempt at a Solution


I don't really know what to use for p, or f
 
Physics news on Phys.org
Did they teach you about the eye?
q = distance from eye lens to retina
p = distance from object viewed to eye lens

Now think - you want the person to see things at p = infinity but you also want them to focus as close-in as possible, given their innate limitation (uncorrected, p = 15cm to p = 40 cm).
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top