A problem in polar i want check my answer

  • Thread starter Thread starter r-soy
  • Start date Start date
  • Tags Tags
    Polar
AI Thread Summary
The discussion revolves around converting the complex number -3 - 5i into polar form. The initial calculation for the modulus (r) is correct at approximately 5.83, but there is confusion regarding the angle (Q). The angle was calculated incorrectly, as the tangent of Q should be based on the correct quadrant for the given coordinates. The need to use radians instead of degrees is emphasized due to the integer values involved. Clarification is sought on the proper calculation of the angle and the correct representation in polar form.
r-soy
Messages
170
Reaction score
1
write in polar form ...elc
-3 - 5i

my answer :

x = -3 y = - 5

r = root (-3)^2 + (-5)^2
= 5.83

tan Q = 5/3 = -1.12
tan-1 -1.12 = -0.84
Q = -0.84
Q = -pi + -0.84 = -3.981

Polar form = 5.83e^(-3.981)i
 
Physics news on Phys.org
Ok first off:
I believe you've recorded your answer in exponential form.

Forms of Complex Numbers:

[PLAIN]https://dl.dropbox.com/u/4645835/MATH/ComplexForms.gif

Please correct me if I'm wrong.
 
Last edited by a moderator:
I think your angle may be wrong as well. This is what I did:

[PLAIN]https://dl.dropbox.com/u/4645835/MATH/Ex1.gif

I can explain why I added 180 degrees to the angle I calculated - if needed.
 
Last edited by a moderator:
Hi

but as I know in this question we change calculator to ( Rad ) nor (deg) because we have integer number -3 and - 5 not roots or ,

and please I want explaine more because I don't understand clearly
 
r-soy said:
write in polar form ...elc
-3 - 5i

my answer :

x = -3 y = - 5

r = root (-3)^2 + (-5)^2
= 5.83

tan Q = 5/3 = -1.12
tan Q = 5/3, but 5/3 is not equal to -1.12
r-soy said:
tan-1 -1.12 = -0.84
Q = -0.84
Q = -pi + -0.84 = -3.981

Polar form = 5.83e^(-3.981)i
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top