A Problem Involving Newton's Second Law

AI Thread Summary
A sky-diver experiences two forces: the downward gravitational force (Fg = mg) and the upward drag force (Fr), which is proportional to velocity (Fr = bv). Applying Newton's Second Law, the net force can be expressed as the difference between these forces, leading to the equation ma = mg - bv. This can be rearranged to express acceleration (a) as a function of velocity (v), resulting in a = g - (b/m)v. The discussion highlights the importance of correctly defining the drag force in relation to velocity to solve the problem effectively.
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Once her chute opens, a sky-diver of mass m is acted upon by a downward force Fg due to gravity, and an upward force Fr due to air resistance. If Fg = mg, where g is gravitational acceleration, and Fr is proportional to velocity v, use Newton’s Second Law of Motion to write acceleration a as a function of velocity v.

Hey guys, I need a help on how to approach this problem. Initially, I assumed Fr = Ff = umg. But the problem states that Fr is proportional to velocity. Help?
 
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Newton's 2nd law is
\sum_i \mathbf{F}_i = m\mathbf{a}What do you get when you apply it to this problem?
 
Proportional meaning, the upward force equals the velocity, times a proportionally constant. Hence the drag force is Fr=bv, where b is a real number and v is velocity.
 
Xyius said:
Proportional meaning, the upward force equals the velocity, times a proportionally constant. Hence the drag force is Fr=bv, where b is a real number and v is velocity.

Thanks Xyius! Using your definition of drag force, I was able to work it out!
 
Glad to hear it! :D!
 
Would you care to explain how you did this?
 
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