A shaft is required to transmit 60kW of power at 4000rev/Minute. Find

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To determine the external diameter of a hollow shaft transmitting 60kW at 4000 RPM, the relationship between power and torque is essential, given by the equation Power = Torque × Angular Velocity. The angular velocity can be calculated from the RPM, converting it to radians per second. The maximum shear stress of 48MPa must be considered, along with the internal diameter being three-quarters of the external diameter, to apply the relevant shear stress formulas. Key equations include those for torque and shear stress in hollow shafts, which will help in solving for the external diameter. Understanding these relationships and equations is crucial for the calculation.
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A shaft is required to transmit 60kW of power at 4000rev/Minute. Find the external diameter required for a hollow shaft if its internal diameter is three quarters of the external diameter. And the maximum permissible shear stress is 48MPa.


can someone help i am confused haven't got a clue how to do it
 
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What are the relevant equations do you think you will need?

How do you relate torque and power?
 

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