A shell is fired vertically upwards

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A shell fired vertically from a moving ship creates a parabolic trajectory as observed from the shore. The horizontal range of the shell can be derived as 2v1v2/g, where v1 is the vertical velocity and v2 is the horizontal velocity of the ship. The motion can be analyzed by treating it as a projectile launched at an angle θ, specifically arctan(v1/v2). Understanding the formulas for parabolic motion, including range, time of flight, and maximum height, is essential for solving the problem. Proper use of the forum's template could have expedited finding the solution.
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A shell is fired vertically upwards with a velocity of v1 from a ship moving with a velocity v2, a person on the shore finds the motion of the shell parabola. Show that the horizontal range is 2v1v2/g
 
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You know the formulas for the parabolic motion?
 
Sure ^_^
For the Range, the Time of Flight and the Max height :)
 
A hint: the problem is like the case in which the shell is fired inclined at a specific angle θ, the angle is to be arctag v1/v2.
 
Yes, because v1 is the velocity in the y direction and v2 the one in x direction.
 
Oh, and: welcome to PF, Driggy. Using the template is compulsory here. If you'd done that you might even have found your answer before actually submitting the post!
 
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