I Accelerate Charged Particle: Does Light Require Force?

MackBlanch
Messages
26
Reaction score
0
Does a charged particle need to experience a momentum changing force to emit light? Or is it sufficient for an observer to accelerate relative to the particle?
 
Physics news on Phys.org
Light emission by a particle is independent of the reference frame. It does not matter what the observer does, it matters if the particle is inertial or not.
 
Sorry, I'm not familiar with the term, "inertial particle".

So, it's not relative motion that drives emission, but changes in a charged particle's momentum?

For instance, if you shake one particle in a two particle system, the shaken particle will not experience an emission from the stationary particle? (at least not before its emission agitates the stationary particle)
 
It comes down to this - if the charged particle accelerates relative to it's electric field, then it will emit. If it does not accelerate relative to it's electric field, it will not emit. The acceleration of the observer relative to the particle and it's electric field does not cause the particle to appear to accelerate relative to its electric field.
 
Inertial = no acceleration
MackBlanch said:
So, it's not relative motion that drives emission, but changes in a charged particle's momentum?
Right.
MackBlanch said:
For instance, if you shake one particle in a two particle system, the shaken particle will not experience an emission from the stationary particle?
Right.
 
  • Like
Likes MackBlanch
mfb said:
Inertial = no acceleration
Right.
Right.

Thanks!
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
Back
Top