Acceleration and distance problem

  • Thread starter Thread starter louisG345
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
A car and a motorcycle start from rest, 1000 meters apart, accelerating towards each other at rates of 3.7 m/s² and 4.4 m/s², respectively. To determine the position where they meet relative to the car's starting point, one must calculate the time it takes for the distance between them to close to zero. The total acceleration towards each other can be used to find this time. Once the time is established, the distance traveled by the car can be calculated using the equation d = (Vi)(t) + 1/2at². This approach will yield the exact position of their meeting point.
louisG345
Messages
1
Reaction score
0

Homework Statement


A car and a motorcycle at rest and 1000.0m apart start toward each other at the same time on a level track. if the car accelerates at a uniform rate of 3.7m/s^2 and the motorcycle accelerates at a uniform rate of 4.40m/s^2, at what position will they pass each other relative to the car's starting point?


Homework Equations


d=(Vi)(t)+1/2at^2
Vf^2=Vi^2+2ad
a=(Vf-Vi)/t


The Attempt at a Solution


i know that the time will be equal but i really just don't know where to go from there or what to do to solve.
 
Physics news on Phys.org
louisG345 said:

Homework Statement


A car and a motorcycle at rest and 1000.0m apart start toward each other at the same time on a level track. if the car accelerates at a uniform rate of 3.7m/s^2 and the motorcycle accelerates at a uniform rate of 4.40m/s^2, at what position will they pass each other relative to the car's starting point?

Homework Equations


d=(Vi)(t)+1/2at^2
Vf^2=Vi^2+2ad
a=(Vf-Vi)/t

The Attempt at a Solution


i know that the time will be equal but i really just don't know where to go from there or what to do to solve.

Homework Statement



Homework Equations



The Attempt at a Solution


Welcome to PF.

First figure how long it will take to close the distance between them to 0.

Maybe if you consider the total acceleration toward each other that can give you the time? And then with that time you can use that for the car and figure the distance it traveled when they meet?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
7
Views
982
Replies
3
Views
863
Replies
11
Views
1K
Replies
5
Views
3K
Replies
1
Views
2K
Replies
2
Views
4K
Back
Top