Acceleration from min/max derivatives

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Homework Help Overview

The discussion revolves around the analysis of a cubic function representing position over time, specifically focusing on the derivatives to find acceleration at critical points. Additionally, a related problem involves determining the optimal time to wind a flywheel for a car to complete a 100-meter race under constant acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of derivatives to find acceleration at specific time points and question the validity of their results. There is also exploration of the implications of constant acceleration in a racing scenario, including considerations of time spent accelerating versus cruising.

Discussion Status

Some participants have provided hints and suggestions for further exploration of the derivative calculations. Others are considering the implications of different strategies for the flywheel car problem, indicating a productive exchange of ideas without reaching a consensus.

Contextual Notes

There are constraints related to the total time for the race, as the time spent winding the flywheel counts towards the overall time. Participants are also grappling with the implications of their calculations and assumptions regarding acceleration and distance.

Turtlie
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Homework Statement


x(t) = -0.01t^3 + t^2 - 20t + 4


Homework Equations


Min is when t = 12.3
Max is when t = 54.4


The Attempt at a Solution


I got -0.03t^2 + 2t - 20 as the derivative.
I substituted in t = 12.3 and 54.4 and got 0.02 and 0.19 which don't seem right at all.
Because: when t is 12.3, the position(x) is -100. When t is 54.4 the position(x) is 250.
 
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Hello Turtlie :smile:

(try using the X2 icon just above the Reply box :wink:)
Turtlie said:
I got -0.03t^2 + 2t - 20 as the derivative.
I substituted in t = 12.3 and 54.4 and got 0.02 and 0.19 which don't seem right at all.

Well, to only 3 https://www.physicsforums.com/library.php?do=view_item&itemid=523" that looks acceptably near zero …

what happens if you solve that quadratic equation to 4 sig figs ? :smile:
 
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Ah looks like I was right then, and thank you for the hint ;)

I've got another question.
A flywheel car is capable of giving a car a constant acceleration of 0.5m/s2, but only for as long as it is wound up for (if it is wound up for 5 seconds it will accelerate at 0.5m/s2. Once the flywheel is finished unwinding it will continue rolling at a constant velocity.

How long should you spend turning the flywheel if the length of the race is 100 meters. The time spent turning the flywheel counts towards the total time.

Honestly I'm completely stuck on this.
 
Turtlie said:
Ah looks like I was right then, and thank you for the hint ;)

I've got another question.
A flywheel car is capable of giving a car a constant acceleration of 0.5m/s2, but only for as long as it is wound up for (if it is wound up for 5 seconds it will accelerate at 0.5m/s2. Once the flywheel is finished unwinding it will continue rolling at a constant velocity.

How long should you spend turning the flywheel if the length of the race is 100 meters. The time spent turning the flywheel counts towards the total time.

Honestly I'm completely stuck on this.

At a constant acceleration of 0.5m/s2, how long will it take the car to go 100m, if it starts from rest?
 
SammyS said:
At a constant acceleration of 0.5m/s2, how long will it take the car to go 100m, if it starts from rest?

ah, but maybe it's better to spend less time winding it, and to let it cruise for the last 10 m or so? :smile:
 

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