Acceleration of a Ball: Understanding the Force of Gravity

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Homework Help Overview

The problem involves understanding the acceleration of a ball thrown straight up with an initial speed of 14 m/s, specifically questioning the nature of acceleration due to gravity at a given time after the throw.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between velocity and acceleration, particularly in the context of gravitational acceleration being constant regardless of the ball's motion direction.

Discussion Status

Some participants have provided clarifications regarding the distinction between velocity and acceleration, emphasizing that the acceleration due to gravity remains constant at -9.8 m/s², regardless of the ball's upward motion. The original poster expresses confusion but acknowledges the clarifications offered.

Contextual Notes

The discussion includes an exploration of the concepts of velocity and acceleration, with emphasis on the directionality of these quantities and the constancy of gravitational acceleration.

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Homework Statement


You throw a ball straight up with a speed of 14m/s. What is the acceleration of the ball 1.5s after you threw it?

Alright, the dilemma I am having is the answer is -9.8m/s^2.

It doesn't make sense to me how the acceleration can be that at 1.5s. The -9.8m/s^2 (gravity of earth) is the force pulling down on the ball not the acceleration after 1.5S as it is still moving up rather then down. What is the correct acceleration, or is -9.8m/s^2 correct?
 
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-9.8 is correct because the time doesn't matter. Gravity will have a constant acceleration on the object. 9.8 is the acceleration, NOT FORCE, because the unit for acceleration is m/s^2
 
-9.8ms-2 is correct. It looks to me like you have velocity and acceleration confused. Velocity is the speed and direction that the ball is moving, acceleration is the speed and direction in which the velocity is changing. This can be a tough concept to grasp (I found it a little difficult at least).

On the ball's way up, every second its velocity will be becoming 9.8ms-1 slower. When it's at its peak, its velocity will be zero, however it can still have an acceleration (9.8ms-2). Then on its way down, it will be speeding up by 9.8ms-1 every second.

From this we can see that the velocity of the ball has completely changed direction, whilst the acceleration hasn't changed at all!

I am aware that I'm not great at explaining things like this, but I hope it's helped a bit until someone else can come and explain the concept better!

Two important things to note are:
acceleration does not have to be in the same direction as velocity, if it's in the opposite direction, it merely means that it's slowing down.
acceleration due to gravity (at levels we're dealing with) does not change.
 
arlight thanks, that clears it up!
 

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