Acceleration of a mass down a decline (tricky)

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The discussion revolves around calculating the tension required to reverse the direction of a 100kg mass moving up a 30-degree incline with a coefficient of kinetic friction of 0.1. The key point is that to reverse the mass's direction in one second, it must decelerate from 2 m/s to 0 m/s, requiring a retardation of 2 m/s², not 4 m/s² as initially calculated. The correct equation incorporates the forces acting on the mass, including friction and gravitational components, leading to a tension value of 387N. Clarifications were made regarding the net forces and the direction of acceleration, emphasizing that the tension acts opposite to the direction of motion. Understanding these dynamics is crucial for accurately solving the problem.
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The plane is inclined at a 30 degree angle. The coefficient of kinetic friction between the mass and the plane is 0.1. The mass is 100kg. If the mass is moving up the inclined plane at a velocity of 2m/s, what tension should be applied to the rope in order to make the mass reverse directions in exactly 1 sec?



mgsin(theta)
mgcos(theta)
Fk = coefficient x mgcos(theta)
V = Vi + at




V = Vi + at a = 4m/s^2
Equation I used to solve:
ma = mgsin(theta) - T - Fk(theta)


My answer was 187N, actual answer is 387N. No idea how I can manipulate the equation to get 200N more.
 
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can you provide a diagram to make it clear?
 
supratim1 said:
can you provide a diagram to make it clear?

ramp.jpg


Found this on google. The diagram in the book is identical, just ignore the hanging mass. I need to find the tension in the rope.
 
First, to make it reverse direction, required retardation, along the inclined plane is 2
0.1 mg cos30 +mg sin30 - T = 2m

Seems the key here is "make the mass reverse directions" , it just means "make the mass to have 0 velocity in 1 sec" but not "make the mass to have -2 in 1 sec"
 
I believe your acceleration is wrong. It should be 2 m/s2 and in the direction opposite it initial velocity. The velocity has to go from 2 m/s to 0 m/sin a time of 1 s.
 
lswtech said:
First, to make it reverse direction, required retardation, along the inclined plane is 2
0.1 mg cos30 +mg sin30 - T = 2m

Seems the key here is "make the mass reverse directions" , it just means "make the mass to have 0 velocity in 1 sec" but not "make the mass to have -2 in 1 sec"

what is 2m?

edit:
I got the 387N by using your equation, but changed the positions of T and 2m. Can you explain the logic behind your equation. I sort of get it, but I need some clarification.

I understand the force of friction and the downward force of the mass are added because they act in the same direction. And T is in the opposite direction, but how do you explain the 2m?
 
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The question stated " make the mass reverse directions in exactly 1 sec" and I thought the retardation should be 2ms^-2 but not 4.

and the 2m means m*a and putting a = 2

Since the direction of retardation is pointing towards the ground, and the Net force in this direction is Friction + Weight component - Tension and the Net acceleration is 2
 
lswtech said:
The question stated " make the mass reverse directions in exactly 1 sec" and I thought the retardation should be 2ms^-2 but not 4.

and the 2m means m*a and putting a = 2

Since the direction of retardation is pointing towards the ground, and the Net force in this direction is Friction + Weight component - Tension and the Net acceleration is 2

So is the acceleration (ma) in the same direction of the Tension?
 
No. Reverse

(Weight pulls down the block and it is the origin of the acceleration downward)
 

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