Acceleration of a Tennis Racket

AI Thread Summary
The discussion focuses on calculating the total acceleration of a tennis racket during a serve, given its mass, angular acceleration, and angular speed. The tangential acceleration is determined using the formula α*r, while centripetal acceleration is calculated with ω²*r. An error was identified in the calculation of centripetal acceleration, specifically the omission of squaring the angular speed. After correcting this mistake, the total acceleration was recalculated. The final result for total acceleration is approximately 16.39 m/sec².
farrah003
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Homework Statement



During a serve, a tennis racket of mass 1.4 kg is given an angular acceleration of 163 rad/sec2. At the top of the serve, the racket has an angular speed of 16 rad/sec.
If the distance between the top of the racket and the shoulder is 1.5 m, what is the total acceleration of the top of the racket?
atotal = m/sec2 ?

Homework Equations



Tangential acceleration = α*r
Centripetal acceleration = ω²*r

The Attempt at a Solution



a = √[at² + ac²]
a = √[(244.5)² + (24)²]
a = 16.3859
 
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farrah003 said:

Homework Statement



During a serve, a tennis racket of mass 1.4 kg is given an angular acceleration of 163 rad/sec2. At the top of the serve, the racket has an angular speed of 16 rad/sec.
If the distance between the top of the racket and the shoulder is 1.5 m, what is the total acceleration of the top of the racket?
atotal = m/sec2 ?

Homework Equations



Tangential acceleration = α*r
Centripetal acceleration = ω²*r
good.

The Attempt at a Solution



a = √[at² + ac²]
yes!
a = √[(244.5)² + (24)²]
a = 16.3859
In calculating ac, you forgot to square the angular speed, ω.
 
ohh hahahah thanks !
 
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