Acceleration of gravity , from a pendulum

AI Thread Summary
A space explorer uses a pendulum of 800 mm to determine gravity on a new planet, observing 24 swings in 1 minute and 20 seconds. The calculated period is 3.33 seconds, leading to the equation T = 2π√(L/g). By solving for g, the explorer finds the acceleration of gravity to be approximately 2.8 m/s². There is a discussion about ensuring the units are correct and clarifying the calculations involved. The final answer is confirmed to be in SI units, specifically meters per second squared.
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Homework Statement



A space explorer lands on a new plant, and he wants to determin the gravity on it. He makes a pendulum with a lengh of 800 mm and he observes it does 24 full swings in 1min and 20 seconds. What is the acceleration of gravity to be from this ?



The Attempt at a Solution



period
=2pie multiplied by square root of (lenth of the pendulum over gravity.

period= 80/24=3.333333. gravity = 2.8

Is this right what i did, any help would be great
 
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Yes, your answer is correct.
 
Well, you are going to have to explain more exactly what you did.

You have determined that 2\pi \sqrt{800/g}= 10/3. Now, exactly how did you solve that equation for g? Also, what units is your answer in? I hate to disagree with Hootenanny but your answer makes no sense until you say what the units are.

(That's not true- I love to disagree with Hootenanny!)
 
In light of HoI's post, I'm assuming that your in S.I. units.
 
Last edited:
well i use equation T=2pi sqrt( L/g) =T and T is 10/3, so i solved for g, since i know the Lengh is 801m, then i got it to meters
 
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