- #1
sterlinghubbard
- 5
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A 2.81 kg hollow cylinder with inner radius 0.29 m and outer radius 0.5 m rolls without slipping when it is pulled by a horizontal string with a force of 47.7 N, as shown in the diagram below.
Its moment of inertia about the center of mass is .5m(r(out)^2 + r(in)^2).
What is the accelereation of the cylinder's center of mass? Answer in units of m/s^2.
What am I doing wrong? I found the Torque of the hollow cylinder by T = F(r). Then I found the angular acceleration by Torque = Interia * Alpha. Inertia was found using the supplied forumula. After finding the angular acceleration I found the Tangential Acceleration by TangentialAcceleration = radius * AngularAcceleration. What am I doing wrong?
Its moment of inertia about the center of mass is .5m(r(out)^2 + r(in)^2).
What is the accelereation of the cylinder's center of mass? Answer in units of m/s^2.
What am I doing wrong? I found the Torque of the hollow cylinder by T = F(r). Then I found the angular acceleration by Torque = Interia * Alpha. Inertia was found using the supplied forumula. After finding the angular acceleration I found the Tangential Acceleration by TangentialAcceleration = radius * AngularAcceleration. What am I doing wrong?