Acceleration overcoming Velocity. Over what time frame?

AI Thread Summary
The discussion focuses on a particle moving in the positive x-direction with an initial speed Vo but experiencing negative acceleration a. The key challenge is determining the second time t2 when the particle returns to its initial position Xo. Participants emphasize that the speed cannot be calculated using the formula V=(X-Xo)/(t-0) due to the presence of acceleration, which affects speed over time. Understanding the relationship between speed and time under constant acceleration is crucial for solving the problem. Clarifying these concepts will help in finding both t2 and the particle's speed at that point.
Maiton
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Homework Statement


A particle leaves its initial position Xo at time t=0, moving in the positive x direction with speed Vo but undergoing acceleration a in the negative x-direction. Find expression for (a) the time when it returns to Xo and (b) its speed when it passes that point



I'm having difficulting finding my second time t2. If I have this I can find the speed with V=(X-Xo)/(t-0). I'm trying to get into this course but am drawing a blank at this time. If someone could give me a few words in an explanation, I'd be greatly appreciative. It may just open my eyes.

Mike
 
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You can't get speed with V=(X-Xo)/(t-0). The speed is not constant, there is acceleration. How does speed depend on time under constant acceleration?
 
What have you tried to find t2?
 

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