Acceleration question -- Deceleration of a baseball being caught by a player

AI Thread Summary
To calculate the acceleration of a baseball caught by a player, the initial velocity is +18 m/s and the final velocity is 0 m/s, as the ball comes to rest. The time taken to stop is 0.5 seconds. Using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, and a is acceleration, the correct calculation yields an acceleration of -36 m/s². This negative value indicates deceleration, meaning the ball is slowing down. Understanding the signs and values in the equation is crucial for accurate results.
Rasofia
Messages
12
Reaction score
0
1. A baseball is traveling at +18 m/s and is caught by a player. The ball is brought to rest in 0.5 s. What is the acceleration of the ball?

Homework Equations


Maybe vf=vi+ at ?

The Attempt at a Solution


This is under a Horizontal Projectiles worksheet by the way...I'm not sure what to do on this one though. At first I thought to use the equation above and make 18 the final velocity since that's how it's caught...but then what would be the initial? So then I thought...okay maybe the initial could be 18 and the final is 0 since it says 'at rest'. I don't know, this is a bit complicated. Well, If I do it the second way, I get 36 m/s^2
 
Last edited by a moderator:
Physics news on Phys.org
Rasofia said:
1. A baseball is traveling at +18 m/s and is caught by a player. The ball is brought to rest in 0.5 s. What is the acceleration of the ball?

Homework Equations


Maybe vf=vi+ at ?[/B]

The Attempt at a Solution


This is under a Horizontal Projectiles worksheet by the way...I'm not sure what to do on this one though. At first I thought to use the equation above and make 18 the final velocity since that's how it's caught...but then what would be the initial? So then I thought...okay maybe the initial could be 18 and the final is 0 since it says 'at rest'. I don't know, this is a bit complicated. Well, If I do it the second way, I get 36 m/s^2[/B]

When you catch a ball in a glove, how fast is it going when it comes to rest?

Is the catcher flung backwards by the ball he has caught? :))

When you are at rest on your couch, do you have any velocity? :wink:

This problem is complicated only because you are over thinking it.
 
SteamKing said:
When you catch a ball in a glove, how fast is it going when it comes to rest?

Is the catcher flung backwards by the ball he has caught? :))

When you are at rest on your couch, do you have any velocity? :wink:

This problem is complicated only because you are over thinking it.

so I'm right, it's 36?
 
Rasofia said:
so I'm right, it's 36?
It appears to be so.
 
  • Like
Likes Rasofia
Rasofia said:
so I'm right, it's 36?
Not quite. The initial speed is carefully stated as "+18m/s". If you plug that in as vi in your "relevant equation" and put vf=0, what exactly do you get for a?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top